A submarine was at a depth of 106.3 feet below sea level. After 5 hours, the submarine was at 481.2 feet below sea level. How far did the submarine travel?(1 point)

The submarine traveled
feet

1 answer

To find out how far the submarine traveled, you need to calculate the difference in depth between its two positions.

  1. Initial depth = 106.3 feet below sea level
  2. Final depth = 481.2 feet below sea level

To find the distance traveled, you subtract the initial depth from the final depth:

Distance traveled = Final depth - Initial depth = 481.2 feet - 106.3 feet = 374.9 feet

Therefore, the submarine traveled 374.9 feet.