A submarine is travelling parallel to the surface of the ocean at a depth of 626m. It begins a constant ascent in order to reach the surface after travelling a distance of 4420m. The ascent takes 35mins.

Question

A.) what angle of ascent or angle of elevation would the submarine need to make to reach the surface in 4420m.

B.) how far did the submarine travel horizontally during its ascent to the surface?

C.) determine the horizontal speed of the submarine during its ascent?

Please show me all the steps !!! Thanks

Answer 1

draw a diagram.
A) sinθ = 626/4420
B) cotθ = x/626
C) v=x/35 m/min