Heat=massice*Lf
massice=2.95E5J/333kJ/kg
= 295 / 333 kg=.88kg
A styrofoam cooler is a cube with side length of 20.0 cm and walls with thickness of 1.9 cm. If the external temperature is 27.0 deg. C and the cooler contains ice and water at 0 deg. C.
How much heat is transferred into the box in 24 hours?
- I got 2.95x10^5 J for this and it was correct, but I can't figure out the second half. I looked up the amount of heat required to melt 1 kg of ice and got 33.4 kJ, so 2.95x10^5 / 334000 J = 8.832 kg but it was wrong. How do I go about figuring out this question?:
>>> How much of the ice in the cooler will melt in 24 hours?
1 answer