for (b) he's in the air for 0.7s
s=Ut+0.5at^2
2.4=0t+0.5(9.8)(t^2)
t=0.7
A stuntman sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. The constant speed of the horse is 10.0 m/s, and the man is initially 2.75 m above the level of the saddle.
(a) What must be the horizontal distance between the saddle and limb when the man makes his move?
m
(b) How long is he in the air?
s
1 answer