Vo = 75.2m/s @ 47o
Xo = 75.2*cos47 = 51.3 m/s.
Yo = 75.2*sin47 = 55.0 m/s.
h = 520 m
a. Yo*t + 0.5g*t^2 = 520 m.
-55*t + 4.9*t^2 = 520
4.9t^2 - 55t -520 = 0
Use Quadratic formula.
Tf = 17.34 s. = Fall time.
Dx = Xo*Tf = 51.3m/s * 17.34s = 890 m
b. Y = Yo + g*t = -55 + 9.8*17.34 = 115 m/s.
V = Xo + Yi = 51.3 + 115i
Tan A = Y/Xo = 115/51.3 = 2.24039
A = 66o or -66o = 66o Below the +x axis.
A stunt pilot is attempting to drop a water balloon from a moving airplane onto a target on the ground. The plane moves at a speed of 75.2 m/s and a 47° above the horizontal when the balloon is released. At the point of release, the plane is at an altitude of 520 m.
(a) How far horizontally, measured from a point directly below the plane's initial position, will the balloon travel before striking the ground?
m
(b) At the point just before balloon strikes the ground, what angle does its velocity make with the horizontal? Give your answer as an angle measured below the horizontal.
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