To find the time at which the stunt person deploys the parachute, we need to set the expression for their height above sea level equal to 500 feet and solve for t:
600 - 16t^2 = 500
Subtracting 500 from both sides:
100 - 16t^2 = 0
Dividing both sides by 16:
- t^2 = -100/16
Simplifying:
t^2 = 25/4
Taking the square root of both sides:
t = ±√(25/4) = ±(5/2)
Since time cannot be negative, we can discard the negative solution, leaving:
t = 5/2
Therefore, the stunt person deploys the parachute at a time of 5/2 minutes, which is equivalent to 2.5 minutes or 2 minutes and 30 seconds.
A stunt person falls from a helicopter 609 feet above sea level for an action movie and deploys a parachute when at a height of 500 feet above sea level. The stunt persons height above sea level is defined by the expression 600-16t^2, where t is the time , in minutes, after the fall.
At what time does the stunt person deploy the parachute ?
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