Using a formula for confidence interval of variance with your data included, we have:
[(6-1)16.8]/(chi-square) to [(6-1)16.8]/(chi-square)
Use values from a chi-square table that equate to a 99% interval using 5 degrees of freedom, then finish the calculation for the interval.
A study of generator related carbon monoxide deaths showed that a sample of 6 recent years had a variance of 16.8 deaths per year. Find the 99% confidence interval of the true variance
2 answers
2.2< o < 14.3