A study found that 81% of households
in the United States have computers. Of those 81%, 92% have Internet
access. Find the probability that a U.S. household selected at random has a
computer and has Internet access.
2 answers
0.745
P(A and B) = P(A) * P(B/A)
= (0.81)* (0.92)
= 0.745
The probability that a U.S. household selected at random has a
computer and has Internet access is 0.745
= (0.81)* (0.92)
= 0.745
The probability that a U.S. household selected at random has a
computer and has Internet access is 0.745