Hi,
Since there is no acceleration in the horizontal direction the calculators would travel a dstance of
(horizontal velocity)X (time of flight)
=27.38
to find the height of the cliff use
D=v0t+1/2AT^2, since there is no initial velcity in the vertical direction cancel to get
D=1/2AT^2 which = 67.081
have fun!
A students stands at the top of a high vertical cliff and throws calculators into the sea. He throws the calculators horizontally with a speed of 7.4 m/s and observes that each reaches the water below 3.7 s after the release. Neglect air resistance and find
(a) How far from the base of the cliff do the calculators strike he water?
(b) How high is the cliff?
1 answer