He should have diluted to 300 mL of _solution_ as opposed to just adding 300 mL of water.
For B, use this:
MV = mass / molar mass
(x) (0.330 L) = 25.7 g / 342.2948 g/mol
x = 0.2275 M
Round to two sig figs is 0.23 M
For C, the difference is 0.02 between the 0.23 and 0.25. The percent error this this:
(0.02 / 0.25) * 100 = 8%
A student wishes to prepare 300 mL of 0.25 M sucrose. He puts 25.7 g of sucrose in a beaker and then adds
300 mL of dH2O. The total volume of the solution after the sucrose has been dissolved is 330 mL.
a) What did he do wrong when preparing his solution?
b) What is the actual concentration of the sucrose solution he prepared?
c) What is the percentage error in the concentration of sucrose from the desired 0.25 M?
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