KHP + NaOH ==> NaKP + H2O
mols KHP = grams/molar mass
The rxn is 1:1; therefore, mols NaOH = mols kHP.
Then M NaOH = mols NaOH/L NaOH
A student weighs out 0.568 g of KHP (molar mass = 204 g/mol) and titrates to the
equivalence point with 36.78 mL of a stock NaOH solution. What is the concentration
of the stock NaOH solution? KHP is an acid with one acidic proton.
a. 3.15 M b. 0.0757 M c. 0.943 M d. 0.100 M e. 1.23 M
1 answer
1 answer