A student wants to calculate the average atomic mass of neon in nature. Information about neon is in the table below.

Isotopes in Nature

Atomic Mass (amu)

Natural Abundance (%)

neon-20

19.992

90.48

neon-21

20.993

.27

neon-22

21.991

9.25

Which of the following is a correct way for the student to set up the calculation?

1 answer

To calculate the average atomic mass of neon using the given isotopes and their natural abundances, the student can set up the calculation as follows:

  1. Convert the natural abundance percentages to decimal form by dividing by 100.

    • For neon-20: \(90.48% = 0.9048\)
    • For neon-21: \(0.27% = 0.0027\)
    • For neon-22: \(9.25% = 0.0925\)
  2. Multiply the atomic mass of each isotope by its corresponding decimal abundance:

    • Neon-20 contribution: \(19.992 , \text{amu} \times 0.9048\)
    • Neon-21 contribution: \(20.993 , \text{amu} \times 0.0027\)
    • Neon-22 contribution: \(21.991 , \text{amu} \times 0.0925\)
  3. Add the contributions from each isotope to get the average atomic mass: \[ \text{Average Atomic Mass} = (19.992 \times 0.9048) + (20.993 \times 0.0027) + (21.991 \times 0.0925) \]

This setup provides the correct method for calculating the average atomic mass of neon based on the isotopes and their natural abundances.