A student walks east 100 meters in minutes. She then walks north 200 meters in 4 minutes. Which statement is true?

Answer 1

To analyze the situation, let's break it down based on the student’s movements:

1. The student walks 100 meters east.
2. Then, the student walks 200 meters north in 4 minutes.

To determine which statement about her movement could be true, we can look at a few key points:

• Total distance traveled: The total distance the student walked is $100\text{ m (east)}+200\text{ m (north)}=300\text{ meters}$.

• Direction of displacement: Her final position would be northeast of her starting point, since she walked east first and then north.

• Time taken for the eastward walk: If the student took $x$ minutes to walk 100 meters east, then her speed during this segment would be $\frac{100}{x}$ m/min.

• Velocity during the northward walk: During the northward walk of 200 meters in 4 minutes, her average speed would be $\frac{200\text{ m}}{4\text{ min}}=50\text{ m/min}$.

Without knowing the specifics of which statements are provided, some true statements we can infer might include:

• The total distance walked is 300 meters.
• The student walked a total of 200 meters north after walking 100 meters east.
• The final position is northeast of the start point.

If any specific statements were given, please provide them, and I can analyze which one is true based on the details we've discussed.