Question

A student walks east 100 meters in minutes. She then walks north 200 meters in 4 minutes. Which statement is true?

Answer 1

To analyze the situation, let's break it down based on the student’s movements:

1. The student walks **100 meters east**.
2. Then, the student walks **200 meters north in 4 minutes**.

To determine which statement about her movement could be true, we can look at a few key points:

- **Total distance traveled**: The total distance the student walked is \( 100 \text{ m (east)} + 200 \text{ m (north)} = 300 \text{ meters} \).
- **Direction of displacement**: Her final position would be northeast of her starting point, since she walked east first and then north.
- **Time taken for the eastward walk**: If the student took \( x \) minutes to walk 100 meters east, then her speed during this segment would be \( \frac{100}{x} \) m/min.

- **Velocity during the northward walk**: During the northward walk of 200 meters in 4 minutes, her average speed would be \( \frac{200 \text{ m}}{4 \text{ min}} = 50 \text{ m/min} \).

Without knowing the specifics of which statements are provided, some true statements we can infer might include:

- The total distance walked is **300 meters**.
- The student walked a total of **200 meters north** after walking **100 meters east**.
- The final position is northeast of the start point.

If any specific statements were given, please provide them, and I can analyze which one is true based on the details we've discussed.