A student walking home at a steady rate of 4.80 m/s suddenly decides to start running. She can accelerate at 7.50 m/s22, and runs for 1.70 s before stopping. What distance did the student cover while running?
1 answer
in this question we see that the only movement ( displacement/distance) that could be done was horizontal distance we started off with 4.80 m/s which was the initial velocity that the person was walking by, the person was walking by this velocity in a constant rate e then the person starts to accelerate by 7.50m/s^2 and the person was able to speed up by this acceleration by running for 1.80s then the person stops we can conclude from this that the final velocity is equal to zero then we can use the formula v^2 = v1^2 +2ad and solve for d hope it helps sorry not sure if this is the right answer