A student titrates a 25.00 mL sample of HCl. If 20.50 mL of 0.175 M of KOH is required to reach the end point, what is the concentration of the HCl?

25.0 mL HCl x 1L/1000 mL x 0.175 M/1 L = 0.004375 mol HCl

0.004375 mol HCl/20.50 mL KOH x 1000 mL/1 L = 0.213 M HCl

(I'm thinking maybe I have the 20.50 mL or KOH and the 25.0 mL HCl in the wrong places, they need to be switched?)

1 answer

You have it messed up. Learn to do it this way.
NormalityAcid=NormalBAse
If you don't know how to convert M to N, learn that. In this case, they are the same.

NormalityHCL*volumeAcit=.175*20.50
MolarityHCL=.175*20.5ml*M/25.0ml
and you have it. it is not your answer above.