A student throws a baseball at a large gong 45 m away and hears the sound of the gong 1.35258 s later. The speed of sound in air is 330 m/s.What was the average speed of the base- ball on its way to the gong? (For simplicity, assume its trajectory to be a straight line.)

Question

A student throws a baseball at a large gong 45 m away and hears the sound of the gong 1.35258 s later. The speed of sound in air is 330 m/s.What was the average speed of the base- ball on its way to the gong? (For simplicity, assume its trajectory to be a straight line.)
Answer in units of m/s

Anonymous · Accepted Answer

Why did you not put the answer

bobpursley · Answer

total time equals the time for the ball to go there, and the time for sound to come back.

time for sound to come back: 330*45
time for ball to go there: v*1.35258

add those, set it to equal the time given.
solve for v.