A student stands on a skateboard and pushes on a wall with a force of 87N [S]. The total mass of the

student and the skateboard is 58kg. Calculate the acceleration of the student.

1 answer

To calculate the acceleration of the student, we can use Newton's second law of motion, which states that the acceleration of an object is proportional to the net force acting on it and inversely proportional to its mass.

The net force acting on the student can be calculated using the force applied by the student and the force of gravity acting on the student:

Net force = applied force - force of gravity

The force of gravity can be calculated using the mass of the student and the acceleration due to gravity (9.8 m/s^2):

Force of gravity = mass * acceleration due to gravity

Let's substitute the given values into these equations:

Force of gravity = 58 kg * 9.8 m/s^2 = 568.4 N

Net force = 87 N - 568.4 N = -481.4 N

Since the force applied by the student is opposing the force of gravity, the net force is negative.

Now, we can calculate the acceleration using Newton's second law of motion:

Acceleration = Net force / mass

Acceleration = -481.4 N / 58 kg ≈ -8.3 m/s^2

Therefore, the acceleration of the student is approximately -8.3 m/s^2. The negative sign indicates that the student is accelerating in the opposite direction of the applied force.