A student solved the following equation using the following steps:

4(2−3x)=x−2(2x+1)
8−3x=x−4x−2
8−3x=−3x−2
No solution.
Based on the students work the equation was solved ( incorrectly or correctly )
The equation solved correctly would show that it has ( one solution, no solution , infinite solutions
or two solutions )

1 answer

Let's analyze the student's work step by step to see if the equation was solved correctly and determine the number of solutions.

The original equation is:

\[ 4(2 - 3x) = x - 2(2x + 1) \]

Step 1: Distribute both sides.

On the left side:

\[ 4(2 - 3x) = 8 - 12x \]

On the right side:

\[ x - 2(2x + 1) = x - 4x - 2 = -3x - 2 \]

So we rewrite the equation as:

\[ 8 - 12x = -3x - 2 \]

Step 2: Now, rearranging the equation to combine like terms.

The student's next step is:

\[ 8 - 3x = -3x - 2 \]

This seems to be incorrect because it doesn't match with our calculations above. The correct form is:

\[ 8 - 12x = -3x - 2 \]

Step 3: Let's solve it correctly:

Add \(3x\) to both sides:

\[ 8 - 12x + 3x = -2 \]

Which simplifies to:

\[ 8 - 9x = -2 \]

Now subtract 8 from both sides:

\[ -9x = -10 \]

Now divide by -9:

\[ x = \frac{10}{9} \]

Conclusion:

The original student claim stated "No solution" is incorrect. The correctly solved equation shows that it has one solution, namely \( x = \frac{10}{9} \).

So, the equation has one solution.