a student separated a 1.50 g sample of sand mixed with salt and obtained 0.70 g of salt and 0.65 g of sand. what percent recovery of the initial mixture was obtained?

Answer 1

You had 1.50 to start; you recovered 0.70 + .65 = 1.35g.
%recovered = (1.35/1.50)*100 = ?

Answer 2

%recovered is 90%