A student rides her bicycle down a hill. Together, she and the bicycle have a mass of 56 kilograms. She is moving at 11 meters per second. What is her kinetic energy?(1 point)

Question

Responses

3,388 J
3,388 J

17,248 J
17,248 J

13,552 J
13,552 J

6,776 J
6,776 J

Answer 1

The kinetic energy (KE) of an object can be calculated using the formula:

\[ KE = \frac{1}{2} m v^2 \]

where:

• \( m \) is the mass of the object,
• \( v \) is the velocity of the object.

Given:

• \( m = 56 \) kg (mass of the student and bicycle),
• \( v = 11 \) m/s (velocity).

Now, substituting the values into the formula:

\[ KE = \frac{1}{2} \times 56 , \text{kg} \times (11 , \text{m/s})^2 \]

First, calculate \( (11 , \text{m/s})^2 \):

\[ (11 , \text{m/s})^2 = 121 , \text{m}^2/\text{s}^2 \]

Now, substitute that back into the kinetic energy equation:

\[ KE = \frac{1}{2} \times 56 , \text{kg} \times 121 , \text{m}^2/\text{s}^2 \] \[ KE = 28 , \text{kg} \times 121 , \text{m}^2/\text{s}^2 \] \[ KE = 3388 , \text{J} \]

Thus, the kinetic energy of the student and her bicycle is 3,388 J.