A student rides her bicycle down a hill. Together, she and the bicycle have a mass of 56 kilograms. She is moving at 11 meters per second. What is her kinetic energy?(1 point)

Question

Responses

6,776 J
6,776 J

3,388 J
3,388 J

13,552 J
13,552 J

17,248 J

Answer 1

To calculate the kinetic energy (KE) of the student and her bicycle, we can use the formula:

\[ KE = \frac{1}{2} m v^2 \]

where:

• \( m \) is the mass (in kilograms),
• \( v \) is the velocity (in meters per second).

Given:

• \( m = 56 \) kg
• \( v = 11 \) m/s

Now, substituting in the values:

\[ KE = \frac{1}{2} \times 56 , \text{kg} \times (11 , \text{m/s})^2 \]

Calculating \( (11 , \text{m/s})^2 \):

\[ (11 , \text{m/s})^2 = 121 , \text{m}^2/\text{s}^2 \]

Now substituting back into the kinetic energy formula:

\[ KE = \frac{1}{2} \times 56 , \text{kg} \times 121 , \text{m}^2/\text{s}^2 \]

Calculating \( \frac{1}{2} \times 56 = 28 \):

\[ KE = 28 , \text{kg} \times 121 , \text{m}^2/\text{s}^2 \]

Now, calculating \( 28 \times 121 \):

\[ 28 \times 121 = 3388 , \text{J} \]

Thus, the kinetic energy of the student and her bicycle is:

\[ \boxed{3,388 , \text{J}} \]