A student prepares a soln that is initally 0.006M Pb2+ and 0.00450M I-. This soln is placed into a 1.00cm wide cuvet and inserted into the spectrometer producing as abosrbance reading of 0.430 at a wavelength of 456nm. What is the equilibrium concentration of the iodide ions in the soln?
From a graoh they give us y=188x+0.0541 where y is absorbance and x is concentration of I-
I plugged inn .430 for y and got
.430=188x+0.0541 x=0.002MI-
Is this all the question is asking?
1 answer
I think you have interpreted correctly IF (that's a big IF) the graph is reading absorbance versus concentration of I^-.
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