Asked by christine
A student performed the freezing point depression experiment according to directions but mistakenly recorded the mass of lauric acid as 8.300g instead of8.003g. The calculated molar mass of the unknown acid will be GREATER/LESS than true value b/c mass of lauric acid appears in the denominator of the unknown acid's molecular weight determination, therefore, if it was mistakenly recorded too high, it would INCREASE/DECREASE the calculated moles of solute.
i think it's less, decrease. am i correct in my thinking?
deltaTf= mass/molarmass * K then
molarmass=mass*k/deltaTf
I don't kinow what the experiment is, but I do know that mass is not in the denominator here. So the question does not read correctly. Here is mass is too high, the calculated molar mass will be too high.
i think it's less, decrease. am i correct in my thinking?
deltaTf= mass/molarmass * K then
molarmass=mass*k/deltaTf
I don't kinow what the experiment is, but I do know that mass is not in the denominator here. So the question does not read correctly. Here is mass is too high, the calculated molar mass will be too high.
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