the masses:
m1 = 27.4850 - 26.4750 = 1.0100 g
do m2 and m3 in the same way
mean mass: (29.5260 - 26.4750)/3 = ____ g
or, (m1+m2+m3)/3
A student performed sequential transfers of one milliliter portions of a liquid into a 50 mL beaker. The masses recorded are as follows:
Mass of beaker: 26.4750 g
Mass after first transfer: 27.4850 g
Mass after second transfer: 28.5000 g
Mass after third transfer: 29.5260 g
Answer the following questions using the given data.
Calculate the mass of each portion of the liquid and the mean mass of a portion of the liquid.
1 answer
1 answer