x = n + (n+1) = 2n+1
y = (n+2)+(n+3) = 2n+5
x y = 62997
(2n+1)(2n+5) = 62997
4 n^2 + 12 n + 5 = 62997
4 n^2 + 12 n - 62992 = 0
n^2 + 3 n -15748 = 0
( n + 127 )( n - 124 ) = 0
124, 125, 126, 127
A student opened her math book and computed the sum of the numbers on two pages. Then, she turned to the next page and computed the sum of the numbers on those two facing pages. Finally, she computed the product of the two sums, and her calculator displayed the number 62,997. What were the four page numbers.
1 answer
1 answer