Divide the net horizontal forward force by the mass.
[173cos27.5 -(M*g -173sin27.5)*ìk]/M = a
M = 27 kg
ìk = 0.2
g = 9.81
Solve for a.
A student moves a box of books down the hall
by pulling on a rope attached to the box. The
student pulls with a force of 173 N at an angle of 27.5� above the horizontal. The box has a
mass of 27 kg, and μk between the box and
the floor is 0.2.
The acceleration of gravity is 9.81 m/s2 .
Find the acceleration of the box.
Answer in units of m/s2
2 answers
-0.232 m/s^2
1 answer