A student measures 0.2452 g of a monoprotic solid acid, and dissolves the solid in water to make 100.0 mL of solution. the entire solution is titrated to a phenolphthalein endpoint with 45.06mL of 0.1725M KOH.

Question

A student measures 0.2452 g of a monoprotic solid acid, and dissolves the solid in water to make 100.0 mL of solution. the entire solution is titrated to a phenolphthalein endpoint with 45.06mL of 0.1725M KOH. 
A. what is the molarity of the acid solution?
B. what is the molar mass of the solid acid?

DrBob222 · Answer

moles KOH = M KOH x L KOH = ? moles unknown acid = moles KOH since the acid is monoprotic. moles acid = grams/molar mass Solve for molar mass.