A student measured the height of a pole as 5.98m, the percentage error made in measuring the height is 5 persent. If this movement is smaller than the exact measurements, find the actual height of the place

1 answer

To find the actual height of the pole when a measurement is made with a certain percentage error, we can use the concept of percentage error to relate the measured value and the actual value.

The formula for percentage error is given by:

\[ \text{Percentage Error} = \left( \frac{\text{Measured Value} - \text{Actual Value}}{\text{Actual Value}} \right) \times 100 \]

In this case, we know the following:

  • Measured Value = 5.98 m
  • Percentage Error = 5%

Since the measured value is smaller than the actual value, we can rearrange the formula to find the actual value:

Let \( x \) be the actual height of the pole. According to the given percentage error:

\[ 5 = \left( \frac{5.98 - x}{x} \right) \times 100 \]

Now, convert the percentage to a decimal by dividing by 100:

\[ 0.05 = \frac{5.98 - x}{x} \]

To eliminate the fraction, multiply both sides by \( x \):

\[ 0.05x = 5.98 - x \]

Next, add \( x \) to both sides:

\[ 0.05x + x = 5.98 \]

This simplifies to:

\[ 1.05x = 5.98 \]

Now, solve for \( x \) by dividing both sides by 1.05:

\[ x = \frac{5.98}{1.05} \approx 5.69857 \]

Thus, the actual height of the pole is approximately:

\[ x \approx 5.70 \text{ m} \] (rounded to two decimal places).

So, the actual height of the pole is approximately 5.70 meters.