Based on the given Punnett square and information about eye color genetics, the student can answer the following two questions:
A. What is the genotype of the female parent?
- The Punnett square indicates that one parent is homozygous (BB), and because it is a square depicting a cross between a homozygous (BB) and a heterozygous (Bb) parent, you can determine that the female parent (homozygous) must have the genotype BB.
E. What is the percent likelihood of an offspring having brown eyes?
- From the Punnett square, there are four potential offspring genotypes: 2 BB (homozygous brown) and 2 Bb (heterozygous brown). Therefore, 100% (2 BB + 2 Bb = 4) of the offspring will have the brown eye trait.
The student cannot answer questions B, C, or D using the information from the provided Punnett square. Thus, the answers are A and E.