at the beginning --- > t = 0
f(0) = 50 - 50e^0 = 0
half-way through course --- > t=10
f(10) = 50 - 50e^2 = -319
your equation makes no sense
Your function is a decreasing function.
Why would the student's speed decrease as the course progresses ?
Check for typo.
A student is in a 20 week calc class. The function f(t)=50-50e^0.2t f(t) measures the students problem speed in t weeks
-how many problems per hour can a student solve at the beginning of the course
- how many problems per hour can a student solve halfway through the course
-at what rate is the students problem speed increasing 6 weeks into the course
2 answers
how to figure out rate
1 answer