Let x be the number of $1 bills and y be the number of $5 bills.
We can set up the following equations based on the given information:
1) x + y = 15 (Equation 1, representing the total number of bills)
2) 1x + 5y = 47 (Equation 2, representing the total value of the bills)
To solve algebraically using the substitution method, we can solve Equation 1 for x in terms of y:
x = 15 - y
Substitute this into Equation 2:
1(15 - y) + 5y = 47
15 - y + 5y = 47
15 + 4y = 47
Combine like terms:
4y = 32
y = 8
Substitute y = 8 back into Equation 1 to solve for x:
x + 8 = 15
x = 7
Therefore, the student has 7 $1 bills and 8 $5 bills.
A student has some $1 and $5 bills in his wallet. He has a total of 15 bills that are worth $47. How many of each type of bill does he have?
1.) Write a system of equations for the problem above.
2.) Solve algebraically (substitution or elimination methods)
1 answer
1 answer