Question

A student has an object with a charge of -3 Coulombs. Which of the following objects would have the strongest attraction to object A?(1 point) Responses An object with a +3 charge at a distance of 5 cm An object with a +3 charge at a distance of 5 cm An object with a -4 charge at a distance of 2 cm An object with a -4 charge at a distance of 2 cm An object with a -3 charge at a distance of 5 cm An object with a -3 charge at a distance of 5 cm An object with a +3 charge at a distance of 2 cm

Answer 1

To determine which object would have the strongest attraction to the object with a charge of -3 Coulombs, we need to consider the charge types and the distances involved.

1. Attraction occurs between opposite charges. Therefore, a positively charged object will attract the negatively charged object (the one with -3 Coulombs).

2. The force of attraction can be calculated using Coulomb's law:
\[ F = k \frac{|q_1 q_2|}{r^2} \]
where \( F \) is the force, \( k \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the magnitudes of the charges, and \( r \) is the distance between them.

Now, let's analyze the options:

1. **An object with +3 charge at a distance of 5 cm**:
\[ F = k \frac{|(-3)(+3)|}{(5 \, \text{cm})^2} \]

2. **An object with -4 charge at a distance of 2 cm**:
Not applicable for attraction (like charges repel).

3. **An object with -3 charge at a distance of 5 cm**:
Not applicable for attraction (like charges repel).

4. **An object with +3 charge at a distance of 2 cm**:
\[ F = k \frac{|(-3)(+3)|}{(2 \, \text{cm})^2} \]

Calculating the pull for the relevant objects:
- For the +3 charge at 5 cm:
\[ F = k \frac{9}{25} \]

- For the +3 charge at 2 cm:
\[ F = k \frac{9}{4} \]

Since \( \frac{9}{4} > \frac{9}{25} \), the object that would have the strongest attraction to the -3 Coulombs charge is:

**An object with +3 charge at a distance of 2 cm.**