A student has 10.0mL of phosphate solution that contains 1.0M PO4{3-}.The Student reacts this with excess ammonium & magnesium under basic conditions to produce 2.2034g of struvite. Calculate the % yield.

Answer 1

Mg^2+ + NH3 + 7H2O + PO4^3- ==> MgNH4PO4.6H2O + OH^-

mols PO4^3- = M x L = 1.0 x 0.010 = 0.010
mols MgNH4PO4.6H2O = 0.010
g MgNH4PO4.6H2O = mols x molar mass = 0.010 x 245.41 = ? This is the theoretical yield.
%yield = (2.2034/?)*100 = ???

Answer 2

yes that's the right answer