Force on the car in the direction of the rope is
F = (489/2)÷sin(θ)
where θ=angle formed by the rope and the car-tree line.
A student gets his car stuck in a snow drift. Not at a loss, having studied physics, he attaches one end of a stout rope to the vehicle and the other end to the trunk of a nearby tree, allowing for a small amount of slack. The student then exerts a force vector F on the center of the rope in the direction perpendicular to the car-tree line, as shown in the figure below. If the rope is inextensible and if the magnitude of the applied force is 489 N, what is the force on the car? (Assume equilibrium conditions.)
1 answer
1 answer