To calculate the initial velocity of the cannonball, we can use the equation for average force:
F = m * Δv/Δt,
where F is the force applied to the cannonball, m is the mass of the cannonball, Δv is the change in velocity of the cannonball, and Δt is the time interval over which the force is applied.
In this case, the average force exerted by the cannon is given as 67,000 N, the mass of the cannonball is 70 kg, and the length of the barrel is 0.76 m.
Since the cannonball is inside the barrel, we can assume that the time interval over which the force is applied (Δt) is the time it takes for the cannonball to travel through the barrel. This can be calculated using the formula: Δt = Δx/v,
where Δx is the length of the barrel (0.76 m) and v is the velocity of the cannonball.
Rearranging the equation F = m * Δv/Δt, we can solve for Δv:
Δv = (F * Δt)/m.
Substituting the given values:
Δv = (67,000 N * 0.76 m) / 70 kg
= 57,520 m/N.
Now, to find the initial velocity of the cannonball, we can use the equation v = Δv + u, where u is the initial velocity (which is 0 m/s, since the cannonball starts from rest):
v = Δv + u
= 57,520 m/N + 0 m/s
= 57,520 m/s.
Therefore, the initial velocity of the cannonball is 57,520 m/s.
A student fires a 70kg cannonball as shown. The cannon exerts an average force of 67000N while inside the .76m long barrel. What’s the initial
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