Or do you do the probability of the clocks not working?
0.1^3=0.001 then subtract from 1 to get the chances of at least 1 working
1-0.001= 0.999.
A student experiences difficulty with malfunctioning alarm clocks. Instead of using one alarm clock, he decides to use three. What is the probability that at least one alarm clock works correctly if each individual alarm clock has a 90% chance of working correctly?
Is the answer as simple as 0.9^3 or is there more to it?
2 answers
You're right.
Probability of an individual clock working properly = 0.9
Probability of an individual clock not working properly = 1 - 0.9 = 0.1
The probability of all three clocks not working properly = ( 0.1 )³ = 0.001
The probability that at least one clock is working properly = 1 - 0.001 = 0.999
Therefore the proabability that at least one clock is working properly
= 1 - 0.001
Probability of an individual clock working properly = 0.9
Probability of an individual clock not working properly = 1 - 0.9 = 0.1
The probability of all three clocks not working properly = ( 0.1 )³ = 0.001
The probability that at least one clock is working properly = 1 - 0.001 = 0.999
Therefore the proabability that at least one clock is working properly
= 1 - 0.001