A student drops a 0.33-kg piece of steel at 42 ∘C into a container of water at 22 ∘C. The student also drops a 0.51-kg chunk of lead into the same container at the same time. The temperature of the water remains the same.

Question

A student drops a 0.33-kg piece of steel at 42 ∘C into a container of water at 22 ∘C. The student also drops a 0.51-kg chunk of lead into the same container at the same time. The temperature of the water remains the same.
Part A : Was the temperature of the lead greater than, less than, or equal to 22 ∘C?
Part B: What was the temperature of the lead?

Anonymous · Accepted Answer

heat out of steel = heat into lead since the steel cooled and the lead warmed to reach 22 deg the lead was colder than 22 deg .33 * Csteel * (42 -22) = .51 * Clead * (22- Tlead)