q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
That's q = delta H in J for 2.13 g.
Then (delta H/2.13)*molar mass KClO4 = dH in J/mol. Convert to kJ/mol.
A student determines the heat of dissolution of solid potassium perchlorate using a coffee-cup calorimeter of negligible heat capacity.
When 2.13 g of KClO4(s) is dissolved in 106.00 g of water, the temperature of the solution drops from 25.00 to 23.17 °C. Based on the student's observation, calculate the enthalpy of dissolution of KClO4(s) in kJ/mol. Assume the specific heat of the solution is 4.184 J/g°C.
1 answer
1 answer