a student decides to construct a capacitor using two conducting plates 30cm on each side. He seprates the plate with a paper dielectric 2.5 that is 8*10 raise to the power -5 mmerters thick. What is the capacitance of the capacitor.
2 answers
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C = epsilon0*K* A/d
where K is the dielectric constant of paper.
d is the plate separation in m
A is the plate area in m^2
epsilono = 8.85*10^-12 Farad/m
You will have to look up K, which will be a dimensionless number greater than 1.
where K is the dielectric constant of paper.
d is the plate separation in m
A is the plate area in m^2
epsilono = 8.85*10^-12 Farad/m
You will have to look up K, which will be a dimensionless number greater than 1.
2 answers