A student constructs a frequency distribution where the frequency of the first class is 8 and a corresponding histogram with the area of the bar in the first class is 80. The frequency for the second class is twice the frequency of the first class. In the histogram, the area of the bar corresponding to the second class is four times the area of the bar corresponding to the first class. What is the frequency of the second class and the area of the bar corresponding to the second class?

asked by kaitlynn

9 years ago

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1 answer

frequency: 2*8=16
area: 4*80=320

answered by Steve

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Question

A student constructs a frequency distribution where the frequency of the first class is 8 and a corresponding histogram with the area of the bar in the first class is 80. The frequency for the second class is twice the frequency of the first class. In the histogram, the area of the bar corresponding to the second class is four times the area of the bar corresponding to the first class. What is the frequency of the second class and the area of the bar corresponding to the second class?

1 answer

frequency: 2*8=16
area: 4*80=320

Ask a New Question or answer this question.

Steve · Accepted Answer

frequency: 2*8=16 area: 4*80=320