A student completes a titration by adding 12.0 milliliters of NaOH(aq) of unknown concentration to 16.0 milliliters of 0.15 M HCl(aq). What is the molar concentration of the NaOH(aq)?

Answer 1

Запишем уравнение реакции:
NaOH + HCl = NaCl + H2O
C NaOH*V NaOH = C HCl*V HCl
где: C NaOH и C HCl - мол�рные концентрации гидрок�ида натри� и хлорида водорода �оответ�твенно, моль/л; V NaOH и V HCl - объемы ра�творов гидрок�ида натри� и �ол�ной ки�лоты �оответ�твенно, л.
Мол�рна� концентраци� NaOH равна:
C NaOH*V = C HCl*V HCl/V NaOH = 0,016*0,15/0,012 = 0,2 моль/л

We write the reaction equation:
NaOH + HCl = NaCl + H2O
C NaOH * V NaOH = C HCl * V HCl
where: C NaOH and C HCl - molar concentration of sodium hydroxide and hydrogen chloride, respectively, mol / l; V NaOH and V HCl - volumes of the solutions of sodium hydroxide and hydrochloric acid, respectively, l.
Molar concentration of NaOH is:
C NaOH * V = C HCl * V HCl / V NaOH = 0,016 * 0,15 / 0,012 = 0,2 mol / l