To solve this problem, we need to understand heat transfer in an isolated system. When two objects at different temperatures come into contact, heat will flow from the hotter object to the cooler one until thermal equilibrium is reached, meaning both blocks will end up at the same temperature.
Initially, Block 1 is at 40°C and Block 2 is at 20°C.
We can apply the concept of conservation of energy. The heat lost by Block 1 will be equal to the heat gained by Block 2:
\[ m_1c(T_{i1} - T_f) = m_2c(T_f - T_{i2}) \]
However, since both blocks are made of the same material (copper) and if we assume they have equal mass, we can simplify the equation:
The final temperature \( T_f \) can be found by averaging the two initial temperatures:
\[ T_f = \frac{T_{i1} + T_{i2}}{2} = \frac{40°C + 20°C}{2} = 30°C \]
So both blocks will eventually equilibrate at a temperature of 30°C.
Now, looking at the provided options:
A. Block 1: 70°C, Block 2: 70°C (Incorrect)
B. Block 1: 30°C, Block 2: 30°C (Correct)
C. Block 1: 20°C, Block 2: 50°C (Incorrect)
D. Block 1: 50°C, Block 2: 20°C (Incorrect)
The correct answer is B. Block 1: 30°C, Block 2: 30°C.
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