a = F/m = 56 / 5.6 = 10m/s^2,
a=10m/s^2 * (1/1600)mi/m=0.00625mi/s^2
A student applies an upward force of 56 N to a 5.6-kg physics textbook. Find the book’s acceleration (positive for up, negative for down). answer in miles/seconds squared.
1 answer