wave velocity=sqrt (tension/(mass/length)
longest wavelength: 1/2 Lambda = 9.31 m long
frequency=speedofwave/wevelength
A string fixed at both ends is 9.31 m long and has a mass of 0.125 kg. It is subjected to a tension of 100.0 N and set oscillating.
(a) What is the speed of the waves on the string?
m/s
(b) What is the longest possible wavelength for a standing wave?
m
(c) Give the frequency of that wave.
Hz
2 answers
he equation of a transverse wave on a string is
y = (4.8 mm) sin[(14 m-1)x + (440 s-1)t]
The tension in the string is 10 N. (a) What is the wave speed? (b) Find the linear density of this string.
y = (4.8 mm) sin[(14 m-1)x + (440 s-1)t]
The tension in the string is 10 N. (a) What is the wave speed? (b) Find the linear density of this string.
1 answer