E = 1/2 kx^2
so plug in your numbers
A stretched spring stores an energy of 25joules when its is extended by 6.7*10-2m. Calculate it force contant
4 answers
if F = k x
then
potential energy stored = (1/2) k x^2
25 = (1/2) k (6.7^2)(10^-4)
k = (50 / 44.9) 10^4 = 1.11*10^4 = 11,100 Newtons/meter
then
potential energy stored = (1/2) k x^2
25 = (1/2) k (6.7^2)(10^-4)
k = (50 / 44.9) 10^4 = 1.11*10^4 = 11,100 Newtons/meter
A body has a uniform 108km/h how far it travel in half minutes
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