A streched spring store an energy of 25j when it is extended by 6.7 ×10-²m. Calculate its force constant

Answer 1

F = kx
E = 1/2 kx^2 = 1/2 Fx so
1/2 F * 0.067 = 25
F = 50/0.067 = 750
k = 750/0.067 = 1125