To find how much heavier a grain of rice is than a strand of hair, we need to subtract the mass of the hair strand (2.17×10^(-5) ounces) from the mass of the grain of rice (0.002 ounces).
0.002 ounces - 2.17×10^(-5) ounces = 0.001999783 ounces
Since the answer is less than 1, we can express it in scientific notation as:
1.999783×10^(-3) ounces.
Therefore, a grain of rice is 1.999783×10^(-3) ounces heavier than a strand of hair.
A strand of hair has an average mass of 2.17×10−5 ounces. A grain of rice has an average mass of 0.002 ounces. How much heavier is a grain of rice than a strand of hair? Express your answer in scientific notation.(1 point)
× ounces
13 answers
so what the answer
Apologies for the confusion in my previous response.
To find how much heavier a grain of rice is than a strand of hair, we need to subtract the mass of the hair strand (2.17×10^(-5) ounces) from the mass of the grain of rice (0.002 ounces).
0.002 ounces - 2.17×10^(-5) ounces = 0.0019783 ounces
To express the answer in scientific notation, we can write it as:
1.9783×10^(-3) ounces
Therefore, a grain of rice is 1.9783×10^(-3) ounces heavier than a strand of hair.
To find how much heavier a grain of rice is than a strand of hair, we need to subtract the mass of the hair strand (2.17×10^(-5) ounces) from the mass of the grain of rice (0.002 ounces).
0.002 ounces - 2.17×10^(-5) ounces = 0.0019783 ounces
To express the answer in scientific notation, we can write it as:
1.9783×10^(-3) ounces
Therefore, a grain of rice is 1.9783×10^(-3) ounces heavier than a strand of hair.
so the answer is
The answer is 1.9783×10^(-3) ounces.
Light travels at an approximate rate of 1.9×105 mi./sec. There are about 3.2×107 seconds in a year. About how many miles does light travel in a year? Write the answer in scientific notation. Express the answer to the exact decimal place.(1 point) miles
To find the distance light travels in a year, we can multiply the speed of light (1.9×10^5 mi/sec) by the number of seconds in a year (3.2×10^7 seconds).
Distance traveled = speed * time
Distance traveled = 1.9×10^5 mi/sec * 3.2×10^7 seconds
To multiply the numerical values, we multiply the coefficients (1.9 * 3.2 = 6.08). For the powers of 10, we add the exponents (10^5 * 10^7 = 10^12).
Distance traveled = 6.08 * 10^12 miles
Expressing the result in scientific notation, the answer is:
6.08 × 10^12 miles
Therefore, light travels approximately 6.08 × 10^12 miles in a year.
Distance traveled = speed * time
Distance traveled = 1.9×10^5 mi/sec * 3.2×10^7 seconds
To multiply the numerical values, we multiply the coefficients (1.9 * 3.2 = 6.08). For the powers of 10, we add the exponents (10^5 * 10^7 = 10^12).
Distance traveled = 6.08 * 10^12 miles
Expressing the result in scientific notation, the answer is:
6.08 × 10^12 miles
Therefore, light travels approximately 6.08 × 10^12 miles in a year.
so the answer is
The answer is 6.08 × 10^12 miles.
u sure
Yes, I am confident that the answer is 6.08 × 10^12 miles.
The average tectonic plate moves at the rate of 0.006 m per year. How many meters would it move in 2×106 years? Write the answer in scientific notation, expressed to the exact decimal place.(1 point) m
To find out how many meters the tectonic plate would move in 2×10^6 years, we can multiply the average rate of movement (0.006 m/year) by the number of years (2×10^6 years).
Distance moved = rate * time
Distance moved = 0.006 m/year * 2×10^6 years
To multiply the numerical values, we multiply the coefficients (0.006 * 2 = 0.012). For the powers of 10, we add the exponents (10^6 * 10^6 = 10^12).
Distance moved = 0.012 * 10^12 meters
Expressing the result in scientific notation, the answer is:
1.2 × 10^10 meters
Therefore, the tectonic plate would move approximately 1.2 × 10^10 meters in 2×10^6 years.
Distance moved = rate * time
Distance moved = 0.006 m/year * 2×10^6 years
To multiply the numerical values, we multiply the coefficients (0.006 * 2 = 0.012). For the powers of 10, we add the exponents (10^6 * 10^6 = 10^12).
Distance moved = 0.012 * 10^12 meters
Expressing the result in scientific notation, the answer is:
1.2 × 10^10 meters
Therefore, the tectonic plate would move approximately 1.2 × 10^10 meters in 2×10^6 years.