A store sells posters. Each poster costs the same amount. During a sale, the store reduces the price of each poster by $ 1.35. Malika spends $7.08 on 2 posters at the sale price. What was the price of 1 poster before the sale?

Answer 1

Let the original price of a poster be denoted as \( p \). During the sale, the price is reduced by $1.35, thus the sale price per poster becomes:

\[ p - 1.35 \]

Malika buys 2 posters during the sale for a total of $7.08. Therefore, we can write the equation for the total cost based on the sale price:

\[ 2(p - 1.35) = 7.08 \]

To solve for \( p \), we first divide both sides of the equation by 2:

\[ p - 1.35 = \frac{7.08}{2} \]

Calculating the right side:

\[ \frac{7.08}{2} = 3.54 \]

Thus, we have:

\[ p - 1.35 = 3.54 \]

Now, we can solve for \( p \) by adding $1.35 to both sides:

\[ p = 3.54 + 1.35 \]

Calculating the right side gives:

\[ p = 4.89 \]

Therefore, the original price of 1 poster before the sale was

\[ \boxed{4.89} \]