A stone with a mass of 10 kg sits on the ground. Gravity acts on the stone at a rate of 9.8 m/s2. What is the normal force acting on the stone, keeping it at rest?(1 point)

Question

Responses

9.8 N
9.8 N

10 N
10 N

1.02 N
1.02 N

98 N

Answer 1

To find the normal force acting on the stone, we can use the equation for weight, which is given by:

\[ \text{Weight} = \text{mass} \times \text{gravity} \]

In this case:

• Mass of the stone (\( m \)) = 10 kg
• Acceleration due to gravity (\( g \)) = 9.8 m/s²

Calculating the weight:

\[ \text{Weight} = 10 , \text{kg} \times 9.8 , \text{m/s}^2 = 98 , \text{N} \]

Since the stone is at rest and there are no other vertical forces acting on it, the normal force (\( N \)) must balance the weight of the stone. Therefore, the normal force is also:

\[ N = 98 , \text{N} \]

So, the correct answer is 98 N.