A stone with a mass of 10 kg sits on the ground. Gravity acts on the stone at a rate of 9.8 m/s2. What is the normal force acting on the stone, keeping it at rest?(1 point)

Question

Responses

98 N
98 N

1.02 N
1.02 N

9.8 N
9.8 N

10 N

Answer 1

To determine the normal force acting on the stone, we can use the formula for weight, which is given by:

\[ \text{Weight} = \text{mass} \times \text{gravity} \]

In this case:

• Mass of the stone = 10 kg
• Acceleration due to gravity \( g = 9.8 , \text{m/s}^2 \)

Now, calculating the weight:

\[ \text{Weight} = 10 , \text{kg} \times 9.8 , \text{m/s}^2 = 98 , \text{N} \]

Since the stone is at rest on the ground, the normal force (which acts upward) is equal to the weight of the stone (which acts downward). Therefore, the normal force is also 98 N.

The correct response is:

98 N